NCERT Solutions Class 12 Maths Chapter 9 Ex 9.1 | Differential Equations

Differential Equations

NCERT EXERCISE 9.1 • ORDER AND DEGREE

💡 Definitions

Order: The order of the highest order derivative appearing in the equation.

Degree: The power of the highest order derivative, when the equation is a polynomial in derivatives.

[Image of order and degree of differential equation examples]

Note: If the equation involves $\sin(y’), \cos(y’), e^{y’}, \log(y’)$, etc., the Degree is Not Defined.

Questions 01 — 03
Find Order and Degree.
1. $\frac{d^4y}{dx^4} + \sin(y”’) = 0$
Highest derivative is $\frac{d^4y}{dx^4}$ (Order 4).
The term $\sin(y”’)$ makes it non-polynomial in derivatives.
Order: 4, Degree: Not Defined
2. $y’ + 5y = 0$
Highest derivative is $y’$ (Order 1).
Power of $y’$ is 1.
Order: 1, Degree: 1
3. $(\frac{ds}{dt})^4 + 3s\frac{d^2s}{dt^2} = 0$
Highest derivative is $\frac{d^2s}{dt^2}$ (Order 2).
Power of $\frac{d^2s}{dt^2}$ is 1. (Ignore power 4 of first derivative).
Order: 2, Degree: 1
Questions 04 — 06
Tricky Cases.
4. $(\frac{d^2y}{dx^2})^2 + \cos(\frac{dy}{dx}) = 0$
Highest derivative is $\frac{d^2y}{dx^2}$ (Order 2).
Contains $\cos(\frac{dy}{dx})$, so it’s not a polynomial in derivatives.
Order: 2, Degree: Not Defined
5. $\frac{d^2y}{dx^2} = \cos 3x + \sin 3x$
Highest derivative is $\frac{d^2y}{dx^2}$ (Order 2).
Power is 1. (Trig functions of $x$ do not affect degree).
Order: 2, Degree: 1
6. $(y”’)^2 + (y”)^3 + (y’)^4 + y^5 = 0$
Highest derivative is $y”’$ (Order 3).
Power of $y”’$ is 2.
Order: 3, Degree: 2
Questions 07 — 10
Standard Forms.
7. $y”’ + 2y” + y’ = 0$
Order: 3, Degree: 1
8. $y’ + y = e^x$
Order: 1, Degree: 1
9. $y” + (y’)^2 + 2y = 0$
Highest derivative $y”$ (Order 2). Power is 1.
Order: 2, Degree: 1
10. $y” + 2y’ + \sin y = 0$
Highest derivative $y”$ (Order 2).
Note: $\sin y$ is allowed. Only trig functions of derivatives (like $\sin y’$) make degree undefined.
Order: 2, Degree: 1
Questions 11 — 12
Multiple Choice Questions.
11. Degree of $(\frac{d^2y}{dx^2})^3 + (\frac{dy}{dx})^2 + \sin(\frac{dy}{dx}) + 1 = 0$
Highest derivative is $\frac{d^2y}{dx^2}$.
However, due to the presence of $\sin(\frac{dy}{dx})$, the equation is not a polynomial in its derivatives.
Correct Option: (D) Not defined
12. Order of $2x^2 \frac{d^2y}{dx^2} – 3\frac{dy}{dx} + y = 0$
The highest order derivative present is $\frac{d^2y}{dx^2}$.
Correct Option: (A) 2
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